Video narration
Walking around a court's outside, how do you find a rectangle's missing length? Perimeter is the distance around the outside. With perimeter 14 cm and breadth 2 cm: 14 − 2 − 2 = 10; 10 ÷ 2 = 5 cm. Subtract both breadths, then split the rest between two equal lengths. Challenge: perimeter 30 cm, breadth 5 cm. [Pause.] 30 = 2 × (L + 5); 15 = L + 5; L = 10 cm. The same 36 cm string: square, 36 ÷ 4 = 9 cm; triangle, 36 ÷ 3 = 12 cm; hexagon, 36 ÷ 6 = 6 cm. Same perimeter, different side lengths. The field: 2 × (230 + 160) = 780 m per round; three rounds, 780 × 3 = 2,340 m of rope. Akshi: 2 × (70 + 40) = 220 m per round; five rounds, 1,100 m. Toshi: 2 × (60 + 30) = 180 m per round; seven rounds, 1,260 m. Toshi ran 160 m farther. Dot grid: 6s + 3d. Count straight units and diagonal units separately; their lengths aren't established as equal. Now count both types on the next figure. Cut the 6 cm by 4 cm paper into equal pieces. When rejoined, count exposed edges, not shared inside edges. Find each perimeter. Can you arrange them for 22 cm? Memory card: known perimeter-work backwards; equal sides-divide; several rounds-perimeter times rounds; dot grid-count straight and diagonal units separately; reshaped pieces-trace exposed edges; runners-distance per round times rounds. So, the missing length is 5 cm: the two 2 cm sides leave 10 cm, shared equally by the two lengths.