Public AI explainer video
Which hops reach the treasure at 24? Hops of 4 land there; so do 2, 3, 6, 8, and 12. Dividing 24 by each leaves no remainder; they're factors: 1, 2, 3,...
Prompt
Create one continuous premium Grade 6 mathematics animation titled “Which Jump Sizes Can Reach 24 Exactly?” Integrate visuals and narration into one master prompt. Use a clean number line from 0 to 24, accurate equal jumps, a target at 24 and readable division equations. Let learners discover the idea before revealing FACTOR. SEQUENCE 1 — TEST A JUMP Visual: 0 → 4 → 8 → 12 → 16 → 20 → 24. The treasure glows. Narration: “A treasure is waiting at 24. Let’s try equal jumps of 4. We land exactly on 24!” SEQUENCE 2 — TRY OTHER JUMP SIZES Visual: animate correct paths: 2: 0 → 2 → 4 → … → 24 3: 0 → 3 → 6 → 9 → 12 → 15 → 18 → 21 → 24 6: 0 → 6 → 12 → 18 → 24 8: 0 → 8 → 16 → 24 12: 0 → 12 → 24 Narration: “Can other jump sizes reach the treasure exactly? Yes. Jumps of 2, 3, 6, 8 and 12 all land exactly on 24.” SEQUENCE 3 — INCLUDE 1 AND 24 Visual: show jumps of 1 reaching 24, then one jump from 0 to 24. Narration: “Even jumps of 1 reach 24 exactly. And one jump of 24 reaches it too.” SEQUENCE 4 — COLLECT SUCCESSFUL JUMPS Visual: show 1, 2, 3, 4, 6, 8, 12, 24. Display exact divisions: 24 ÷ 1 = 24; 24 ÷ 2 = 12; 24 ÷ 3 = 8; 24 ÷ 4 = 6; 24 ÷ 6 = 4; 24 ÷ 8 = 3; 24 ÷ 12 = 2; 24 ÷ 24 = 1. Narration: “Each of these jump sizes divides 24 exactly, with no remainder. These numbers are the factors of 24.” SEQUENCE 5 — NON-EXAMPLE Visual: jump size 5 goes 0 → 5 → 10 → 15 → 20 → 25, passing the treasure. Display 24 ÷ 5 = 4 remainder 4. Narration: “A jump of 5 does not land exactly on 24. There is a remainder, so 5 is not a factor of 24.” SEQUENCE 6 — QUICK THINK AND BRIDGE Visual: ask “Which jump sizes are factors of 24?” options 5, 6, 7, 8, 12. Pause, then reveal 6, 8 and 12. End with factors of 24 and preview two treasures labelled 14 and 36. Narration: “Which jump sizes reach 24 exactly: 5, 6, 7, 8 or 12? The correct answers are 6, 8 and 12. Next, what if we have two treasures? Can one jump size reach both?” Do not introduce common factors yet. Do not introduce prime factorisation, greatest common factor or least common multiple.
Narration
Which hops reach the treasure at 24? Hops of 4 land there; so do 2, 3, 6, 8, and 12. Dividing 24 by each leaves no remainder; they're factors: 1, 2, 3, 4, 6, 8, 12, and 24. Five hops pass 24 to 25; 24 divided by 5 leaves remainder 4, so 5 isn't a factor. Quick check: 5, 6, 7, 8, or 12? The answers are 6, 8, and 12. Could one hop reach both 14 and 36?
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