Resolving an Airplane's Velocity Vector

Scene 1: Introduction to Velocity Vectors & Vector ResolutionVisuals / Animation: A clean 2D/3D physics diagram showing a coordinate grid (X-axis and Y-axis). An airplane takes off from the origin point at an angle $\theta = 60^\circ$ above the horizontal X-axis. A glowing green arrow represents the main velocity vector $V = 100\text{ m/s}$. Moving Objects:The airplane moves smoothly along the inclined vector path. Two perpendicular dashed projection lines drop from the tip of the vector onto the X and Y axes. A horizontal vector arrow $V_x$ expands along the X-axis, and a vertical vector arrow $V_y$ expands up the Y-axis. On-Screen Text:Vector Resolution $V_x = V \cos \theta$ $V_y = V \sin \theta$ Voiceover (English): "To analyze motion in two dimensions, we resolve any velocity vector $V$ into two perpendicular components: a horizontal component $V_x$ along the ground, and a vertical component $V_y$ along the vertical axis." Scene 2: Airplane Problem Solution (Calculating Components)Visuals / Animation: The airplane continues climbing in the sky. Floating formula boxes appear step-by-step next to the trajectory. Moving Objects: The horizontal arrow $V_x$ glows in blue, showing its calculated value. The vertical arrow $V_y$ glows in red, displaying its value. On-Screen Text:Given: $V = 100\text{ m/s}$, $\theta = 60^\circ$ $V_x = 100 \times \cos(60^\circ) = 50\text{ m/s}$ $V_y = 100 \times \sin(60^\circ) \approx 86.6\text{ m/s}$ Voiceover (English): "For an airplane taking off at $100\text{ m/s}$ at $60$ degrees, its horizontal velocity component is $50\text{ m/s}$, while its vertical velocity component is $86.6\text{ m/s}$."