ToMotion AI logo
Menu
Back to gallery

Public AI explainer video

Magnetic Damping: e-Fold Oscillation Count

Isliye oscillation lagbhag samanya SHM jitni tez rehti hai, par uski amplitude ki outer envelope lagatar ghatati hai: A = A0 exp[-bt/(2m)]. Sawal...

Prompt

Source idea used to generate this video.

Hey, can you create a solution to the problem I have attached in the image?

Narration

Narration used to create this video.

Video narration

Isliye oscillation lagbhag samanya SHM jitni tez rehti hai, par uski amplitude ki outer envelope lagatar ghatati hai: A = A0 exp[-bt/(2m)]. Sawal energy ke e guna ghatne ka nahin hai. Sawal amplitude ke e-fold ka hai, yani amplitude A0 se ghatkar A0/e hone ka. Isliye A/A0 = 1/e rakhiye. Exponential mein exponent minus one hona chahiye, atah bt/(2m) = 1, aur e-fold time t = 2m/b milta hai. Ab is samay ko oscillations mein badalna hai. Weak damping mein period ko lagbhag undamped period le sakte hain: T approx 2pi sqrt(m/k). Isliye oscillation count hai N = t/T = R sqrt(mk)/(pi B^2l^2). Ab values rakhen: R = 10 ohm, m = 0.050 kilogram, k = 0.5 newton per metre, B = 0.1 tesla, aur l = 0.10 metre. Unit conversion mein centimetre ko metre aur gram ko kilogram karna zaroori hai. In values ko substitute karne par N lagbhag 22.5 aata hai. Arthat amplitude e ke factor se ghatne tak patti kareeb 22 oscillations poore karti hai.